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2/5x^2=360
We move all terms to the left:
2/5x^2-(360)=0
Domain of the equation: 5x^2!=0We multiply all the terms by the denominator
x^2!=0/5
x^2!=√0
x!=0
x∈R
-360*5x^2+2=0
Wy multiply elements
-1800x^2+2=0
a = -1800; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-1800)·2
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{14400}=120$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*-1800}=\frac{-120}{-3600} =1/30 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*-1800}=\frac{120}{-3600} =-1/30 $
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